Сompound Cu(NO3)2, also known as copper(II) nitrate, reacts with NaOH, sodium hydroxide, to form Cu(OH)2, copper(II) hydroxide, and NaNO3, sodium nitrate.
To find the result of this reaction, we need to balance the equation and determine the state symbols for each compound.
First, we will balance the equation by making sure the number of each element is equal on both sides of the equation.
On the left side of the equation, we have one copper atom (Cu), while on the right side, we have one copper atom within Cu(OH)2. The number of nitrogen (N) and oxygen (O) atoms remains the same on both sides of the equation.
However, on the left side, we have two nitrogen atoms within the Cu(NO3)2 compound, so we need to balance this by having two nitrogen atoms on the right side. This can be achieved by multiplying NaNO3 by 2 in the final equation.
Similarly, on the left side, we have twelve oxygen atoms within the Cu(NO3)2 compound (2 nitrogen atoms x 6 oxygen atoms), so we need to balance this by having twelve oxygen atoms on the right side. This can be achieved by multiplying Cu(OH)2 by 6 in the final equation.
Now, let"s determine the state symbols for each compound:
Cu(NO3)2 - This is a salt and will be in the aqueous state (aq).
NaOH - Sodium hydroxide is a strong base and will also be in the aqueous state (aq).
Cu(OH)2 - Copper(II) hydroxide is a blue solid and will be in the solid state (s).
NaNO3 - Sodium nitrate is a salt and will be in the aqueous state (aq).
Thus, the result of the reaction between concentrated Cu(NO3)2 and NaOH is the formation of a blue solid called Cu(OH)2 and the formation of aqueous NaNO3.
Please note that this explanation is simplified for a student"s understanding. In reality, there could be more complex forms of copper hydroxide formed in different conditions.
Shura 47
Complete equation for this reaction is as follows:\[Cu(NO_3)_2 + 2NaOH \rightarrow Cu(OH)_2 + 2NaNO_3\]
Сompound Cu(NO3)2, also known as copper(II) nitrate, reacts with NaOH, sodium hydroxide, to form Cu(OH)2, copper(II) hydroxide, and NaNO3, sodium nitrate.
To find the result of this reaction, we need to balance the equation and determine the state symbols for each compound.
First, we will balance the equation by making sure the number of each element is equal on both sides of the equation.
On the left side of the equation, we have one copper atom (Cu), while on the right side, we have one copper atom within Cu(OH)2. The number of nitrogen (N) and oxygen (O) atoms remains the same on both sides of the equation.
However, on the left side, we have two nitrogen atoms within the Cu(NO3)2 compound, so we need to balance this by having two nitrogen atoms on the right side. This can be achieved by multiplying NaNO3 by 2 in the final equation.
Similarly, on the left side, we have twelve oxygen atoms within the Cu(NO3)2 compound (2 nitrogen atoms x 6 oxygen atoms), so we need to balance this by having twelve oxygen atoms on the right side. This can be achieved by multiplying Cu(OH)2 by 6 in the final equation.
Balanced equation:
\[Cu(NO_3)_2 + 2NaOH \rightarrow Cu(OH)_2 + 2NaNO_3\]
Now, let"s determine the state symbols for each compound:
Cu(NO3)2 - This is a salt and will be in the aqueous state (aq).
NaOH - Sodium hydroxide is a strong base and will also be in the aqueous state (aq).
Cu(OH)2 - Copper(II) hydroxide is a blue solid and will be in the solid state (s).
NaNO3 - Sodium nitrate is a salt and will be in the aqueous state (aq).
Thus, the result of the reaction between concentrated Cu(NO3)2 and NaOH is the formation of a blue solid called Cu(OH)2 and the formation of aqueous NaNO3.
Please note that this explanation is simplified for a student"s understanding. In reality, there could be more complex forms of copper hydroxide formed in different conditions.