ABC is a parallelogram with BC = 10 cm, BA = 8 cm, and angle B equal to 60°. Find the area of triangle S(ABC
ABC is a parallelogram with BC = 10 cm, BA = 8 cm, and angle B equal to 60°. Find the area of triangle S(ABC) and the area of parallelogram S(ABCD). SΔABC = 3–√ cm²; S(ABCD) = 3–√ cm². Respond!
Милашка 32
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